in a rotating wheel
Well, just how much energy can you store in a wheel? Why doesn't anyone patent an energy storage device with a wheel? They probably have, so my question is then ... why don't we see electrical storage devices using rotating wheels? What's the trouble?
Let's get some elementary math together I want a replacement for the car's gas tank capable of storing the energy of, say, 10 gallons of gas. energy released by one gram of gasoline = 5.o x 10^{4} joules one gallon of gas is 2620 grams So, ten gallons of gasoline releases about 2620 x 10 x 5 x 10^{4} = 1,310,000,000 joulesNow, I want to put all that energy in the rim of a rotating wheel, so I can use simply mv^{2} for the energy in a rotating wheel because I'm just going to do a ballpark calculation for the rim of the wheel. It's not totally accurate but 90% accuracy is good enough here. The size of the wheel is critical here. About two feet in diameter is about as big as I'm willing to go. The wheel will have to rotate inside of a sphere so that the wheel can precess 360^{o} every day with the earth's rotation. If not, the car might just flip over on its back every day ... not too good for control in traffic. So, whatever energy is put into the wheel must be extracted with electrical pickups and magnets, etc. ... that would seem doable so we needn't get into that at this stage of inquiry. Now, the mass of the wheel is important. More mass and we can have more energy stored per gram ... but ... more mass means more centrifugal force trying to tear the wheel apart. Therein lies the goal of this page. What kind of force is there that will bust this thing apart thereby making it not feasible? Let's go with fifty kilograms or a little over one hundred pounds. 50 kgSo that, v2 = 1.31 x 10^{9} joules 50 kilograms then, v = about 5000 meters per secondWell, that's about five kilometer per second. Pretty fast. Let's see what kind of force that will yield on 1 of, say, 10 spokes about 1/4 meters long inside the wheel. The centrifugal force will be mv^{2}/rso that yields 50 kg x (5 x 10^{3})m^{2} = ~5 x 10^{9} Newtons^{} .25 mWhich in pounds is ... about a billion pounds. Now we can further cut that down to a tenth since we've postulated ten spokes ... so, it's about ... roughly equivalent to the weight of American Airlines entire fleet ... I think
Well, that's why we don't see energy contained in a rotating wheel for cars as a replacement for that gas tank. We don't have anything to hold that kind of force in a confined space to make it useful. There has been some talk about very large wheels to store electrical power for cities. One can imagine a much larger and heavier wheel with a lower speed being used as a temporary storage device. If the centrifugal force were held down to reasonable levels, that could be a help in smoothing out the supplydemand problems in the electrical supply. But it's a no go for automobiles as far as I can see ... for any foreseeable future.
