Nuclear Force

force related to the vertical component of the reaction velocity arises because of the combined effects of the isotropic and positional fields.

Because both positional and isotropic fields are necessary the objective measure of distance must be a composite of both. And because the positional field changes whereas the isotropic does not, at some point the positional field will dominate the definition of distance.

In the positional field, unit field density demands that 'equal' vertical distances be measured off on concentric spheres so that the distance from sphere #2 to sphere #3 is the same as the distance from sphere #3 to #4 even though when judged by the isotropic standard (#2 to #3) appears to be less than (#3 to #4). How then is distance to be measured?

Unit density follows from unit length. The sides of a cube of unit length constitute a unit cube of unit density. In the positional field, the analogous cube is formed by four vertical segments and two shells. Clearly, if the lines are extended the next smaller cube will have insufficient 'space' unless its density is defined as increased, i.e. each sucessive cube is a smaller version of the one atop it and is defined as a unit cube.
This requirement causes the positional field to differ from the isotropic grid in its curvature (any circumnavigation of a particle is always the same finite distance as measured by the vertical lines of the positional field) and in the measure of vertical lengths (the distance between two particles is always infinite as measured by the positional fields' successive shells).

Therefore, two particles separated by an isotropic distance [S] will be in the next instant at either [S+1] or [S-1] depending on the direction taken by the vertical component of the reaction velocity (S given in Compton wavelengths).
The diference between these two states may be regarded as a force if the greater number, S / (S-1), corresponds to a greater probability.

S / (S-1) > (S+1) / S

At 1/2 Compton wavelength the 'force' becomes repulsive since at S less than 1/2 any direction taken by the reaction velocity will take the particle farther away from the other.
At S = 1, the force will be at greatest attraction because S/ (S-1) approaches infinity while (S+1)/S approaches 2.

This qualitive description matches the observed characteristics of the nuclear force.

Nuclear decay consists of the separation of a particle into two daughter particles by the 'random walk' method.

Here, the particle is prevented from 'walking' away from its present position at faster than light speeds by self-interaction with its own field. But the temporary acceleration of the particle by this mechanism results in an ellipsoidal field which has two centers each of which is no more nor less real than the other.
If both these particles, real and virtual, manage to 'walk' off in different directions for a time based on the strength of the nuclear force (which tends to hold them together), they will become separate particles subject to other rules of stability or decay (see Weak Interaction).

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